Question

(b) A 1000 kg vehicle moving with a speed of 20 m/s is
brought to rest in a distance of 50 metres :
fi) Find the acceleration.
fii) Calculate the unbalanced force acting on the vehicle.​

Answer 1

Answer:

Given,

Initial velocity(u)=20ms

−1

Final velocity(v)=0

Distance moved(S)=50m

We know,

v

2

=u

2

+2aS

0=20

2

+2a×50

−400=100a

a=

100

−400

a=−4ms

−2

Now,

F=ma

F=1000×−4

=−4000N

Explanation:

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