b) A 300 a wire Is stretched between 2 7 cm apart. If the tension in the wire is 10OR N. find C wie S Tirst, second, and third harmonic. Here R is your registration number.
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Answer:
In fundamental mode ,
wavelength = 2 × Length of wire
Given,
Mass density = Mass of wire/length of wire = 3.5 × 10^-2/length of wire = 4 × 10^-2
Length of wire = 4/3.5 = 0.875 m
wavelength = 2 × length of wire
= 2 × 0.875 m
= 1.75 m
speed of wave = frequency × wavelength
= 45 × 1.75
= 78.75 m/s
Use formula,
Tension =( speed of wave)² × mass density
= (78.75)² × 4 × 10^-2
= 248.06 N
Explanation:
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