Math, asked by pratigya67, 10 months ago

(b-a)/(a-c) +(c-b)/(b-a) +(a-c)/(c-b)

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Answered by SwaggerGabru
0

Answer:

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Answered by ankushsaini23
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Answer:

\huge\boxed{\fcolorbox{red}{pink}{Your's Answer}}

 = (b - a) + (c - b) + (a - c)

 = (a - c)(b - a)(c - b)

 = (b - a)( {b - a})^{2} (c - b)( {c - b})^{2} (a - c)( {a - c})^{2}

 = (a - c)(b - a)(c - b)

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