b. A ABC is an isosceles triangle in which AB = AC. D and E are the midpoints
of sides AB and AC and DE = 3.5 cm. Find the perimeter of S ABC,
when AD = 4.5 cm.
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Answer:
A ABC is an isosceles triangle in which AB = AC. D and E are the midpoints
of sides AB and AC and DE = 3.5 cm. Find the perimeter of S ABC,
when AD = 4.5 cm.
Step-by-step explanation:
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AD=DB=4.5cm [midpoint]
In ΔABC & ΔADE
∠A=∠A [common angle]
AD
AB
=
AE
AC
=2
∴ By SAS property of triangles ΔABC∼ΔADE
AD
AB
=
DE
BC
=2
So BC=2×DE
=2×3.5=7
Perimeter of ΔABC=4.5+4.5+7=4.5+4.5
=9+7+9
=25cm.
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