Question

b. A ABC is an isosceles triangle in which AB = AC. D and E are the midpoints
of sides AB and AC and DE = 3.5 cm. Find the perimeter of S ABC,
when AD = 4.5 cm.​

Answer 1

Answer:

A ABC is an isosceles triangle in which AB = AC. D and E are the midpoints

of sides AB and AC and DE = 3.5 cm. Find the perimeter of S ABC,

when AD = 4.5 cm.​

Step-by-step explanation:

Please  mark  me the  Brainliest

AD=DB=4.5cm [midpoint]

In ΔABC & ΔADE

∠A=∠A [common angle]

AD

AB

​  

=  

AE

AC

​  

=2

∴ By SAS property of triangles ΔABC∼ΔADE

AD

AB

​  

=  

DE

BC

​  

=2

So BC=2×DE

=2×3.5=7

Perimeter of ΔABC=4.5+4.5+7=4.5+4.5

=9+7+9

=25cm.