Math, asked by mridulapril15, 1 month ago

b) A bag contains 5 black and 7 white balls. A second bag contains 8 black and 3 white balls. One bag is selected at random and a ball is drawn
from it. Find the probability that the ball drawn is white. (15 marks)​

Answers

Answered by nityajariwala2511
0

Answer:

Total no. of balls in the bag is 15 (7 red, 5 black and 3 white)

Solution(i):

No. of red balls in bag is 7

Therefore,

7

C

1

( Selecting 1 out of 7 items) times out of

15

C

1

( Selecting 1 out of 15 items) a red ball is picked.

Let E be the event of drawing a red ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

15

C

1

7

C

1

=

15

7

Solution(ii):

No. of black or white balls in bag is 8 (5 black and 3 white)

Therefore,

8

C

1

( Selecting 1 out of 8 items) times out of

15

C

1

( Selecting 1 out of 15 items) a black or white ball is picked.

Let E be the event of drawing a black or white ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

15

C

1

8

C

1

=

15

8

Solution(iii):

No. of non-black balls in bag is 10 (7 red and 3 white)

Therefore,

10

C

1

( Selecting 1 out of 10 items) times out of

15

C

1

( Selecting 1 out of 15 items) a non-black ball is picked.

Let E be the event of drawing a non-black ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

15

C

1

10

C

1

=

15

10

=

3

2

Answered by LOVEFAMILY
0

Step-by-step explanation:

TOTAL NO OF BALLS IN BOTH BAGS = 5+7+8+3=23

TOTAL NO OF WHITE BALLS IN BOTH BAGS = 7+3=10

TOTAL NO OF BLACK BALLS IN BOTH BAGS= 8+5=13

P(WHITE BALLS) =NO OF WHITE BALLS / TOTAL NO OF BALLS

= 10/23

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