B) a body of mass 500g is kept at rest. a constant force of 6 newton
starts acting on it. find the time taken by the body to move to a distance of
1.2 km.
Answers
Answered by
26
Given :
Mass , m = 500 g = 0.5 kg
Initial velocity , u = 0 m/s
Force , F = 6 N
Distance , s = 1.2 km = 1200 m
Formula Applied :
where ,
- s denotes distance
- u denotes initial velocity
- a denotes acceleration
- t denotes time
- F denotes force
- m denotes mass
Solution
- F = 6 N
- m = 0.5 kg
- s = 1200 m
- u = 0 m/s
- a = 12 m/s²
Answered by
51
Given :-
- Mass = 500g = 0.5kg.
- Force = 6N.
- Distance = 1.2km.
- Initial Velocity = 0m/s.
To Find :-
- Time taken by the body.
Solution :-
We know that,
✰ F = ma ✰
Put the values.
➠ 6 = 0.5 × a.
➠ a = 60/5.
➠ a = 12m/s²
Now, Apply Second Equation Of Kinematics.
❂ s = ut + 1/2 at² ❂
➜ 1200 = 0t + 1/2 × 12 × t²
➜ 1200 = 6t²
➜ t = √200 = 14.14 Approx.
Hence, Your Answer is 14.14 seconds.
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