Question

(Ā+B)(A+C)(B+C)=(Ā+B)(A+C) SOLVE BY BULEAON BIJGANIT

Answer 1

LHS=(b+a)(b+c)(a'+c)=(b+ac)(a'+c)=ba'+bc+0+ac as aa'=0, (where a' denotes the complement of a) =ac+ba'+bc=ac+b(a'+c)=0+ac+b(a'+c)=aa'+ac+b(a'+c)= a(a'+c)+b(a'+c)=(a+b)(a'+c)=RHS. We have used distributivity of + over. and of. over + as well as cc=c.