Question

(b) A can do a piece of work in 2 days. B can do it in 3 days and C in 6 days. If they all work together, the time taken to finish the work is ​

Answer 1

A can do work in 2 days.
So A's daily work = 1/2

B can do work in 3 days
So B's daily work = 1/3

C can do work in 6 days

So C's daily work = 1/6

If all work together, then the total daily work = 1/2 + 1/3 + 1/6
= 3/6 + 2/6 + 1/6

= 6/6
= 1

So, they complete the work in 1 day if they work together.

I hope this helped!

Answer 2

Answer:

1 day

Step-by-step explanation:

let the amount of work = 10 units

Rate of working for :-    (rate = amount of work/no. of days)

A -->

       =10/2

       =5 work/day

B -->

      = 10/3

      =3.333 work/day

C -->

      = 10/6

      = 1.667 work/day

when they work together -->

rate of working = 5+3.333+1.667

                         = 10 work/day

by rearranging the rate equation,

                          no. of days = amount of work / rate

Here,

amount of work is the same (10 units)

rate is 10 when they work together

so, no. of days = 10/10

                           = 1 day