Question

b) A cell in open circuit has emf of 2 volt. In a closed circuit having a
current of 0.05A, the potential difference across the terminals of the cell
is 1.5 volt. Calculate the internal resistance of the cell.​

Answer 1

Explanation:

Internal resistance is measured in Ohms. The relationship between internal resistance (r) and emf (e) of cell s given by. Where, e = EMF i.e. electromotive force (Volts), I = current (A), R = Load resistance, and r is the internal resistance of cell measured in ohms.