Question

b) A copper wire has a resistance of 500 at 20°c and resistance of 580 n at 60 с. Determine
the temperature coeliicient of resistance,
08. a) Obtain an expression for the magni​

Answer 1

Answer:

$\\\tt \dfrac{4 \ \times \ 10^{-3}}{1^{\circ}C}$

Explanation:

Using relation:

$\\\tt R_{final} = R_{inital}[1+ \alpha(T_{final}-T_{inital})]$

Here,

$\\\tt \ Let \ R_{final} = 580 \ and \ T _{final} = 60^{\circ}\\\\\tt R_{initial} = 500 \ and \ T _{initial} = 20^{\circ}$

Substituting the values,

$\\\tt 580= 500 [1+ \alpha(60^{\circ}-20^{\circ})]\\\\\tt Solving \ this \ gives \ \alpha = \dfrac{0.004}{1^{\circ}C} = \dfrac{4 \times 10^{-3}}{1^{\circ}C}$