Question

. (b)
A current of 500 m
A current of 500 mA flows in a series circuit containing an electric
lamp and a conductor of 10 ohm when connected to 6 V battery. Find
the resistance of the electric lamp.​

Answer 1

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Answer 2

Answer:

R = 2 ohm

Explanation:

As per given information, current through series circuit is 500mA or 0.5 A.

Voltage across the series network is 6 V.

We know that in series the voltage is divided and current stays the same.

Voltage drop at 10 ohm conductor = V = I x R

V = 0.5 x 10 ohm

V = 5 Volts

It means that voltage drop across lamp = 6 - 5 = 1 volt

Now resistance of lamp will be;

R = V / I

R = 1 / 0.5

R = 2 ohm