Question

b) A cyclist starting from rest accelerates at a rate of 1 m/s and reaches a velocity of
3 m/s. Find the time taken.
V
TE​

Answer 1

Answer:

Explanation:v=u+at

v=3m/s

u=0 at rest

a= 1m/s^2

t=?

3=0+1×t

3=t

t=3seconds

Answer 2

Correct Question

A cyclist starting from rest accelerates at a rate of 1 m/s² and reaches a velocity of

3 m/s. Find the time taken by the cyclist.

Solution-

A cyclist starting from rest means the initial velocity of the cycle is 0 m/s. Acceleration of the cycle is 1 m/s² and reaches a velocity of 3 m/s.

We have to find the time taken by the cyclist.

From above data we have; u is 0 m/s, v is 3 m/s and a is 1 m/s².

First equation of motion:

v = u + at

Second equation of motion:

s = ut + 1/2 at²

Third equation of motion:

v² - u² = 2as

Using the First Equation Of Motion i.e. v = u + at

Substitute the known values in the above formula,

→ 3 = 0 + (1)t

→ 3 = 0 + t

→ 3 = t

Therefore, the time taken by the cyclist is 3 sec.