Question

b) A cyclist starting from rest accelerates at a rate of 1 m/s² and reaches a velocity of
3 m/s. Find the time taken.

Answer 1

Explanation:

a=v-u/t

1m/s²= 3m/s-0m/s ÷t

1m/s²×t= 3m/s

t=3m/s ÷ 1m/s²

time taken= 3 Seconds.

Answer 2

Given:-

• Initial velocity = 0 m/s (because the body was kept at rest initially)

• Accelaration = 1 m/s²

• Final velocity = 3 m/s

To Find:-

• Time taken by the cyclist

By Applying 1st Kinematical equation :-

$\longrightarrow \large \underline{ \boxed{ \sf{ v = u + at}}} \bigstar$

Where, v, u, a and t represents Final velocity, initial velocity, Accelaration and time taken respectively.

➜ $\sf v = u + at$

➜ $\sf 3 = 0 + 1 \times t$

➜ $\boxed{\boxed{\sf 3 = t }}\bigstar$

hence, time taken is 3 seconds.

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