Question

b. A cylindrical vessel of diameter 14 cm and height 42 cm is fixed symmetrically inside

a similar vessel of radius 8 cm and height 42 cm. The total space between the two

vessels is filled with glass – wool for heat insulation. Find the volume of the glass –

wool required.​

Answer 1

$volume = \pi \: ( {r2}^{2} - {r1}^{2} ) - \times h$

$= \pi( {8}^{2} - {7}^{2} )\times 42$

$= \pi(64 - 49) \times 42$

$= \pi(15 \times 42)$

$= 630\pi$

$= 630 \times \frac{22}{7}$

$= 1980 {cm}^{3}$

Answer 2

Answer:

volume=π(r2

2

−r1

2

)−×h

= \pi( {8}^{2} - {7}^{2} )\times 42=π(8

2

−7

2

)×42

= \pi(64 - 49) \times 42=π(64−49)×42

= \pi(15 \times 42)=π(15×42)

= 630\pi=630π

= 630 \times \frac{22}{7} =630×

7

22

= 1980 {cm}^{3} =1980cm

3

Step-by-step explanation:

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