Question

b) A dielectric of dielectric constant 5.0 is filled in the gap between the plates of a
capacitor. Calculate the factor by which the capacitance is increased, if the
dielectric is only sufficient to fill up 1/5 of the gap.​

Answer 1

Answer:

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Answer 2

Answer:

C

0

=

d

ϵ

0

S

C=C_1+C_2=\frac{\epsilon\epsilon_0(1/5)S}{d}+\frac{\epsilon_0(4/5)S}{d}=C=C

1

+C

2

=

d

ϵϵ

0

(1/5)S

+

d

ϵ

0

(4/5)S

=

=\frac{\epsilon_0S}{d}(\epsilon/5+4/5)=

d

ϵ

0

S

(ϵk=\frac{C}{C_0}=\epsilon/5+4/5=5/5+4/5=1.8k=

C

0

C

=ϵ/5+4/5=5/5+4/5=1.8

Explanation:

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