Question

b) A dog runs 100 m in 20 seconds. He then comes back half the distance in 10
seconds and stops. What is the dog's average velocity?
1 ko is kept at rest. A constant force of 6 N starts acting on it. Find​

Answer 1

Answer:

5m/s (because distance is given and not the displacement)

Explanation:

Dog runs 100m in 20s

velocity = 100/20(m/s)

             = 5m/s --V1

Now the dog runs 50m back in 10s

So. the velocity = 50/10(m/s)

                          = 5m/s --V2

Average velocity = sum of velocities / no. of velocities

                             = 5 + 5 / 2

                             = 10 / 2

                             = 5 m/s

(I can't understand the second bit of the question so, I am finding work done on a displacement of 1 m)

1 kg is at rest

constant force = 6N

displacement = 1m(considering)

work done = 6N * 1m

                  = 6Nm or 6Joules