Question

b) A floor is 40 m long and 15 m broad. It is covered with tiles, each measuring 3 m by 4 m. Find the number of tiles required to cover the floor?​

Answer 1

Step-by-step explanation:

Area of rect = l×b=Area of floor =40m×15m=600m

Area of rect =l×b=Area of tiles =3m×4m=12m

No.of tiles required = 600m÷12m=50m

Ans =50m

Answer 2

Given,

Length of the floor = 40 m.

Breadth of the floor = 15 m.

Area of the floor = l×b = 40×15 = 600m².

Now,

Length of 1 tile = 3 m =

Breadth of 1 tile = 4 m =

Area of 1 tile = 3 m × 4 m = 12 m

$Tiles\: required \: = \: \frac{600}{12} tiles$

$\: \:\: \: \:\:\: \:\:\: \:\:\: \:\: \: \:\:\: \:\:\: \:\:\: \:\:\: \: \:\:= \: 50 tiles$