Physics, asked by amrishsinghratan, 3 months ago

b) A loud symphonic passage produces an intensity level of 70 dB. A person
speaking normally produces a sound level of 40 db. Compare their intensities.​

Answers

Answered by ItzYourJaani
5

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Answered by priyadarshinibhowal2
0

\frac{I_{1} }{I_{2}} = 10^{3}.

  • The power carried by sound waves per unit area in a direction perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square metre is the SI unit of intensity, which also covers sound intensity. One use for this technology is to measure the amount of sound energy present in the air near a listener.
  • Sound pressure and sound intensity are two different physical quantities. Sound pressure, which is correlated with sound intensity, is sensitive to human hearing. While level differences are referred to as "intensity" differences in consumer audio electronics, sound intensity is a precisely defined quantity that cannot be detected by a straightforward microphone.
  • A logarithmic expression of sound intensity in relation to a reference intensity is called sound intensity level.

Here, according to the given information,

A loud symphonic passage produces an intensity level of 70 dB. Then, n_{1} =70.

Similarly, n_{2} =40.\\

Now, I_{1} = I_{0} .10^{\frac{70}{10} } =I_{0} .10^{7 }

Again, I_{2} = I_{0} .10^{\frac{40}{10} } =I_{0} .10^{4 }.

Then, \frac{I_{1} }{I_{2}} = 10^{3}.

Hence,  \frac{I_{1} }{I_{2}} = 10^{3}.

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