Question

(b) A man is thrice as old as his son. Five years ago the man was four times
as old as his son.Find their present ages.
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Answer 1

Answer:

PLZ MARK AS BRAINLIEST !

Step-by-step explanation:

Let the age of son be x

Let his father's age be 3x

Five years ago, age of son = x - 5

Five years ago, age of father = 3x - 5

5 years ago the man was four times as old as his son = 4(x - 5)

According to the question,

3x - 5 = 4(x - 5)

3x - 5 = 4x - 20

3x - 4x = -20 + 5

x = 15

Present age of son is x

=> 15 years

Present age of father =. 3x

=> 3 * 15

=> 45 years

∴The  age of son and his father is 15 years and 45 years respectively.

Answer 2

Answer:

SON 15 FATHER 45

Step-by-step explanation:

son age x

father age 3×x

five years ago

son x-5

father 3x-5

father age = 4x-20

go mean future

ago mean past

3x-5=4X-20

3X-4X=-20+5

-1X= -15

X=15

SON AGE 15

FATHER 45