b) A man throws a ball of mass 150g to a wall with a velocity 20 m/s and it re bounce with same velocity. Find the change in momentum in this process? (2)
Answers
Answered by
7
Answer:
0
Explanation:
Change in momentum = mv - mu
where m - mass = 150g = 0.15Kg
v - final velocity = 20m/s
u - initial velocity = 20m/s
Change in momentum = mv - mu
= m (v - u)
= 150 (20 - 20 )
= 150 × 0
= 0
∴ there is no change in momentum
Answered by
4
Answer:
We know that Force = Impulse / Time
Impulse = mass * change in velocity
Time = 0.01s
Mass m = 150g
= 1.5 x10^-1 kg
Change in velocity = Final - Initial Velocity = 20 - (-20) =40 m/s
Therefore,
Force = mass * change in velocity / time
= 1.5 X 10^-1 X 40 / 0.01
= 15 X 40
= 600
Average force on the Ball is 600N
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