(b) A meter rule of weight 150gf is pivoted in such a way that it is maintained in
equilibrium by suspending weights of 35gf and 90gf from the 70cm and 85 cm
mark respectively. Calculate the point on the meter at which it is pivoted .[3]
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Torque due to load =4N×40cm=1.6Nm
Torque due to weight of the rule =2N×10cm=0.2Nm
Both are in opposite to each other so net torque =1.6−0.2=1.4Nm
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