Question

b. A person standing between two vertical cliffs which are 1280m apart, shouts.
He hears the first echo after 3s and the second echo 2s later. Calculate:
i)
The distance of nearest cliff from the person.
ii) The speed of sound.​

Answer 1

Answer:

(i) Total distance travelled by the sound in going and coming back (in the case of the nearest cliff) =2×480 m

Speed of sound =

Timetaken

Totaldistancetravelled

=

3

2×480

=320m/s

ii)Time taken to reach second echo=3+2=5 s

Now v=

t

2d

⇒ d=

2

vt

Distance of the other cliff from the person =

2

320×5

=800m

Explanation:

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