Question

(b) A racing car has a uniform acceleration of 8 m/s. What distance will it cover

12 s after the start?​

Answer 1

Given :

• Initial velocity, u = 0 m/s
• Time, t = 12 seconds
• Acceleration, a = 8 m/s²

To find :

• Distance covered by the racing car, s

According to the question,

By using Newtons second equation of motion,

➞ s = ut + ½ at²

Where,

• s = Distance
• u = Initial velocity
• a = Acceleration
• t = Time

➞ Substituting the values,

➞ s = 0 × 12 + ½ × 8 × 12 × 12

➞ s = 0 + 4 × 144

➞ s = 0 + 576

➞ s = 576

• So, the distance covered by the racing car is 576 metres.

____________________

More formulas :

Newtons first equation of motion :

• v = u + at

Newtons second equation of motion :

• s = ut + ½ at²

Newtons third equation of motion :

• v² = u² + 2as

Answer 2

Hey, sorry for being late (new to this app)
Ur answer-
Given
a= 8m/s
t=12s
u=0m/s
s=.?
Solution
s=ur+1/2at²
s=1/2x8x144
=576m
Hopefully it’s right