Question

(b) A rubber ball of mass 0.12 kg is held at a height of 2.5m above the ground and then released
Calculate K.E of the ball just before it hits the ground​

Answer 1

Explanation:

Change in potential energy = Kinetic Energy

m*g*h = (1/2)*m*(v^2)

9.8 * 2.5 * 2 = v^2

49 = v^2

v = 7 m/s

Answer 2

Answer:

2.94. Hope you mark it as brainilist and thank even follow if possible