Question

(b)
A sample of 0.50 g of an organic compound was treated according
to Kjeldahl's method. The ammonia evolved was absorbed in 50 ml
of 0.5 MH,SO,. The residual acid required 70 mL of 0.5 M solution
of NaOH for neutralisation. Find the percentage composition of
nitrogen in the compound.​

Answer 1

Answer:

Explanation:

difference in equivalents of h2so4 gives equivalent of ammonia

=15

moles*f*1000=15

moles=0.015

weight = 1.47

ammonia weight = 1.47

percentage of nitrogen = 14/17*1.47/0.5*100