Question

b) A spherical ball of weight 50N is suspended vertically

by string 500mm long. Find the magnitude and direction

of the least force, which can hold the ball 100mm above

the lowest point. Also find tension in the string at that

point. 7​

Answer 1

Answer:

I don't know this answer really bro

Answer 2

Given info : A spherical ball of weight 50N is suspended vertically by string 500mm long.

To find : the magnitude and direction of the least force, which can hold the ball 100mm above the lowest point is..

also the tension in the string at that point is..

solution : draw free body diagram,

sinθ = 3/5 and cosθ = 4/5

at equilibrium state,

Tsinθ = Fcosθ

⇒T(3/5) = F(4/5)

⇒3T = 4F ....(1)

again, Tcosθ + Fsinθ = mg

⇒T(4/5) + F(3/5) = 50N

⇒4T + 3F = 250 ...(2)

from equations (1) and (2),

F = 30N and T = 40 N

Therefore the tension in the string at that point is 40N and minimum force is 30N and the direction of force, tanθ = 3/4 along North East .