(b)A stone is dropped from the edge of the roof.
(i) How long does it take to fall 19.6m?
(ii) How fast does it move at the end of that fall?
(iii) What will be its acceleration after 2 sec and after 3 secs?
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Given :-
☄ Initial velocity, u = 0 m/s (dropped)
☄ Height of the stone from the ground, h = 19.6 m
☄ Acceleration due to gravity, g = 9.8 m/s²
To find :-
(i) How long does it take to fall 19.6m?
(ii) How fast does it move at the end of that fall?
(iii) What will be its acceleration after 2 sec and after 3 secs?
Solution :-
(i) by using 2nd equation of motion .i.e.,
thus, the time taken by the stone to fall 19.6 m is 2s
(ii) by using 1st equation of motion .i.e.,
thus, the final velocity of the stone is 19.6 m/s
(iii) using 1st first equation of motion .i.e.,
thus, the acceleration of the ball after 2 s is 9.8m/s²
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