Question

b)A stone is thrown vertically upwards with an initial velocity of 40 m/s .Find the
maximum height reached by the stone .What is net displacement and distance covered
by the stone.?

Answer 1

Answer:

The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero

Step-by-step explanation:

Final velocity v = 0

Initial velocity u = 40m/s

We know that,

Using equation of motion

 

The maximum height is

The  stone will reach at the top and will come down

Therefore, the total distance will be

The net displacement is

Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero

Answer 2

Step-by-step explanation:

the maximum height is 80m and the total distance covered by stone is 160m and the displacement is zero