b) A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)
Answers
Answer:
A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)
Step-by-step explanation:
A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)
A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)A swimming pool of dimensions 40m x 30m x 5m needs to be tiled with tiles of dimension
20cm x 20cm. If one tile costs Rs. 1.5. find the total cost of tiling (walls and floor)
Answer:
Length of swimming pool l=30m
Breadth of swimming pool b=20m
Height of swimming pool h=1.5m
The total surface area of pool= Lateral surface area + Area of base
=2h(l+b)+(l×b)
=2×1.5(30+20)+(30×20)
=750m
2
Side of square tile a=50cm=0.5m
Area of 1 tile =a×a=0.5×0.5=0.25m
2
Number of tiles =
area of tile
area of pool
=
0.25
750
Number of tiles =3000
Therefore 3000 tiles are required.