B. A truck starts from rest and rolls down a hill with a constant
acceleration. It travels a distance of 400 m in 20 s. Find its
acceleration. Find the force acting on it if it's mass is
7 tonnes (Hint: 1 tonne = 1000 kg.)
Answers
Answer: 14000 N
Given parameters
Initial velocity (u) = 0
Distance travelled (s) = 400 m
Time taken (t) = 20 s
Find out
The force acting on it if its mass is 7 metric tons
Solution
1 metric ton = 1000 kg
7 metric ton = 7 × 1000 = 7000 kg
∴ Mass (m) = 7000 kg
We know the formula
\(s = ut + \frac{1}{2}at^{2}\)
Substitute the given parameters in the above equation
400 = 0 + ½ a (20)2
400 = a × 400/2
400 = 200 × a
a = 2 m/s2
Acceleration is equal to 2 m/s2
Force (F) = Mass (m) × Acceleration (a)
Substitute the values of mass and acceleration in the above equation, we get
F = 7000 × 2
F = 14000 N
Answer
The force acting on it if its mass is 7 metric tons is 14000 N
Answer:
14000 N
Given parameters
Initial velocity (u) = 0
Distance travelled (s) = 400 m
Time taken (t) = 20 s
Explanation:
1 metric ton = 1000 kg
7 metric ton = 7 × 1000 = 7000 kg
∴ Mass (m) = 7000 kg
We know the formula
\(s = ut + \frac{1}{2}at^{2}\)
Substitute the given parameters in the above equation
400 = 0 + ½ a (20)2
400 = a × 400/2
400 = 200 × a
a = 2 m/s2
Acceleration is equal to 2 m/s2
Force (F) = Mass (m) × Acceleration (a)
Substitute the values of mass and acceleration in the above equation, we get
F = 7000 × 2
F = 14000 N
Answer
The force acting on it if its mass is 7 metric tons is 14000 N