Question

b/a x+a/b y=a2+b2 and x+y=2ab

Answer 1

Step-by-step explanation:

Solution for x and y.

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2→ b2 x a2y = a3 b - a2y

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2→ b2 x a2y = a3 b - a2y→ b2 (x-ab) = a2 (ab - y)

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2→ b2 x a2y = a3 b - a2y→ b2 (x-ab) = a2 (ab - y)from eq2 ----- b2 (x - x/2 + y/2)

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2→ b2 x a2y = a3 b - a2y→ b2 (x-ab) = a2 (ab - y)from eq2 ----- b2 (x - x/2 + y/2)= a2 (x/2 + y/2 - y)

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2→ b2 x a2y = a3 b - a2y→ b2 (x-ab) = a2 (ab - y)from eq2 ----- b2 (x - x/2 + y/2)= a2 (x/2 + y/2 - y)→ b2 ( x/2 - y/2) = a2 (x/2 + y/2)

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2→ b2 x a2y = a3 b - a2y→ b2 (x-ab) = a2 (ab - y)from eq2 ----- b2 (x - x/2 + y/2)= a2 (x/2 + y/2 - y)→ b2 ( x/2 - y/2) = a2 (x/2 + y/2)→ b2 x - b2y = a2x - a2y

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2→ b2 x a2y = a3 b - a2y→ b2 (x-ab) = a2 (ab - y)from eq2 ----- b2 (x - x/2 + y/2)= a2 (x/2 + y/2 - y)→ b2 ( x/2 - y/2) = a2 (x/2 + y/2)→ b2 x - b2y = a2x - a2y→ x = y --------

Solution for x and y. bx / a ay / b = a2 + b2 ----- eq 1x+y = 2ab ------- eq 2from eq1 ----- b2x + a2 ab = a2 + b2→ b2 x a2y = a3 b - a2y→ b2 (x-ab) = a2 (ab - y)from eq2 ----- b2 (x - x/2 + y/2)= a2 (x/2 + y/2 - y)→ b2 ( x/2 - y/2) = a2 (x/2 + y/2)→ b2 x - b2y = a2x - a2y→ x = y --------put the value of x in eq2 ----- 2y = 2ab.