Question

b) Al + Fe, 03 —> Al2O3 + Fe (Atomic masses : Al = 27 U,
Fe = 56 U, O = 16 U)
In the above chemical reaction calculate the quantity of Iron formed when
108 kg of aluminium is consumed.​

Answer 1

Answer:

108g means 4 atoms of aluminium

so, 1atom of Al need 1 atom of Fe

4 atoms of aluminium need 4 atoms of iron

so 56 * 4 = 224g