Question

(b) An element having atomic mass 60u has FCC lattice, the edge length of the unit cell 400pm.
Calculate the density of the crystal (NA = 6.022 x 1023)​

Answer 1

Answer:

Use the formula, =z. MNA. a3; where d is the density, z is the number of atoms per unit cell, M is the molecular or atomic mass in g/mol, NA is the Avogadro's number and 'a' is the edge length. Therefore the density of the unit cell is 6 gcm−3.