Math, asked by minecraftanuj, 5 months ago

(b) An object is moving with a velocity of 6 m/s and with an acceleration of - Im/s. What will be the
(i) distance travelled by the object before it coming to rest?
(ii) time taken for coming to rest​

Answers

Answered by kikibuji
100
  • Initial velocity of the object, u = 6 m/s

  • Acceleration of the object ,a = -1 m/s².

Since the object comes to rest, the final velocity of the object is zero.

  • Final velocity, v = 0

  • Let s be the distance travelled by the object.

  • Let t be the time taken for coming to rest.

ii)

According to the first equation of motion,

v = u + at

0 = 6 +  (- 1 \times t) \\  \\  0- 6 =  - t \\  \\ t = 6 \: s

The time taken by the object for coming to rest is 6 s.

I)

According to the third equation of motion,

 {v}^{2}  -  {u}^{2}  = 2as \\  \\  {0}^{2}  -  {6}^{2}  = 2 \times ( -1 ) \times s \\  \\  - 36 =  - 2s \\  \\ s =  \frac{36}{2}  \\  \\ s = 18 \: m

The distance travelled by the object is 18 m.


amansharma264: nyccc
shadowsabers03: Good
prince5132: Great
Answered by BrainlyShadow01
140

Correct Question:-

An object is moving with a velocity of 6m/s and comes to rest with a deceleration of 1m/s². Then find the distance travelled by the object and also find the time taken by the object to come to rest.

To Find:-

  • Find the distance travelled by the object.
  • Time taken by the object to come to rest.

Given:-

  • An object is moving with a velocity of 6m/s and comes to rest with a deceleration of 1m/s².

Solution:-

Here,

We know that

  • initial velocity = 6m/s
  • final velocity = 0
  • acceleration = -1m/s²

Using Formula:-

 \frak \red {v = u + at}

Substituting value:-

\tt\implies \: 0 = 6 + -1(t)

\tt\implies \: 0 = 6 - t

\tt\implies \: t = 6sec

Now,

We have to find the distance.

Using Formula:-

 \frak \red {s = ut + \dfrac{1}{2} \times {at}^{2} }

Substituting Values:-

\tt\implies \: s = 6(6) +  \dfrac{1}{2}  \times -1 \times 6 \times 6

\tt\implies \: s = 36 - 18

\tt\implies \: s = 18m


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prince5132: Awesome
Anonymous: Awesome
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