Question

(b) An object of mass 1 kp is travelling in a straight line with a velocity of 10m\s collides with
and sticks into a wooden block of mass 5 kg. Then they both move off together with same
velocity in the same direction. Calculate the velocity of the combined object.​

Answer 1

Answer:

5/3 ms^-1

Explanation:Given,

m = 1kg, u1=10ms^-1, M=5kg, u2=0ms^-1

From conservation of momentum

Initial momentum=Final momentum

mu1 + Mu2 = (m + M)v

1 × 10 + 5 × 0 = (1 + 5)v

10=6v

Hence, velocity of both is (v)= 5/3ms^-1

                                           

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