b) An object of mass 40 kg is been acted upon by a force that changes its velocity from 30 km/h to 25 km/h
How much work is done by the force? Is the work done negative or positive?
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Explanation,
Given,
- Mass of an object (m) = 40 kg
- Initial velocity (u) = 30 km/h
- Final velocity (v) = 25 km/h
To Find,
- Work done by the force? is the work done negative or positive?
Solution,
Firstly, convert km/h into m/s,
Initial velocity (u) = 30 km/h
⇒ u = 30 × 5/18
⇒ u = 1.6 × 5
⇒ u = 8 m/s
Final velocity (v) = 25 km/h
⇒ v = 25 × 5/18
⇒ v = 1.3 × 5
⇒ v = 6.5 m/s
According to the work - Energy theorem,
Work done = Change in kinetic energy
.°. W = ΔK.E
⇒ W = ¹/2 × m × (v² - u²)
⇒ W = ¹/2 × 40 × (6.5² - 8²)
⇒ W = 20 × (42.25 - 64)
⇒ W = 20 × -21.75
⇒ W = -435 J
Therefore,
The work done by the force is -435 J and is the work done negative.
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