Question

B and q any 2 points lined on the side DC and AD of a parellogram ABCD show that ar(apb) = at (bqc)

Answer 1

$\huge\underline\mathfrak{\red{✨ANSWER✨}}$

It can be observed that ΔBQC and parallelogram ABCD lie on the same base BC and these are between the same parallel lines AD and BC.

∴Area (ΔBQC) = 1/2 Area (ABCD) ... (1)

Similarly, ΔAPB and parallelogram ABCD lie on the same base AB and between the same parallel lines AB and DC.

∴ Area (ΔAPB) = 1/2 Area (ABCD) ... (2) From equation (1) and (2), we obtain Area (ΔBQC) = Area (ΔAPB)