Question

B
Aracing car acceleratas uniformly from
18.5 ms to 46.1ms in 2.47 seconds.
Determined the acceleration of the car and
the distance travelled.
​

Answer 1

acceleration

a=v-u

-----

t

a=46.1-18.5

-------------

2.47

a=38.6 m/s^2

distance

s=ut+1/2at^2

s=18.5×2.47+1/2×38.6×2.47×2.47

s=163.4 km

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