Question

(b) At a place the vertical component of earth's magnetic field is
0.3 gauss and angle of dip is 45°. Calculate the total intensity of
earth's magnetic field and its horizontal component.
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Answer 1

Answer:

Here, B  H =0.3G, B  V =0.52G

The earth's magnetic field

B=$\sqrt{= BH2+BV2}$ =$\sqrt{(0.3) 2+(0.52)2}$ =0.6G

and angle of dip, tanδ=  

BH /BV =  0.3 /0.52 =1.734

δ=tan  

−1 (1.734)=60° .

Explanation: