Question

b + (b+1) + (b+2)/4 = 21

Answer 1

Answer:

$\frac{b + (b + 1) + (b + 2)}{4} = 21 \\ b + (b + 1) + (b + 2) = 21 \times 4 \\ b + b + 1+ b + 2 = 84 \\ b + b + b + 1 + 2 = 84 \\ 3b + 3 = 84 \\ 3(b + 1) = 84 \\ b + 1 = \frac{84}{3} \\ b + 1 = 28 \\ b = 28 - 1 \\ b = 27$