Question

b+ ( b+ 1)+( b+2)÷4=21​

Answer 1

b+(b+1)+(b+2)÷4=21

3b+3÷4=21

3b=21-4

3b=18

b=18/3

b=6

the three no are

b=6

b+1=6+1=7

b+2=6+2=8

Answer 2

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b = 26/3

step-by-step explanation :

Given,

b +(b+1) + (b +2)÷ 4 = 21

on simplifying,

we get,

(2b + 1) + [tex]\frac{(b+2)}{4}/tex] = 21

On taking the L.C.M of denominators and simplifying,

we get,

=> 4(2b + 1 )+ ( b+2) = 21 × 4

( doing cross-multiplication )

=> (8b + b) + (4+2) = 84

=> 9b = 84 - 6

=> 9b = 78

=> b = 78/9

=> b = 26/3.