Question

B + ( B/4 ) * 7 + [( B*2 ) - ( B-2 ) ( B-2 )] + 5 - ( B*B ) = B​

Answer 1

Given: The expression B + ( B/4 ) * 7 + [( B*2 ) - ( B-2 ) ( B-2 )] + 5 - ( B*B ) = B

To find: Value of B?

Solution:

• As we have given a very long equation, we first need to simplify it and make it into quadratic equation.

         B + 7B/4 + 2B - ( B-2 )² + 5 - B² = B

         B + 7B/4 + 2B - ( B² - 4B + 4 ) + 5 - B² = B

         7B/4 + 2B - ( B² - 4B + 4 ) + 5 - B² = 0

         7B/4 + 2B - B² + 4B - 4 + 5 - B² = 0

         7B/4 + 6B + 1 - 2B² = 0

         31B + 4 - 8B² = 0

         8B² - 31B - 4 = 0

Now we can find the value of B by using quadratic form.

         B = -b±√D / 2a

         B = 31 ± √31² + 4(8)(4) / 16

         B = 31 ± √961 + 128 / 16

         B = 31 ± √1089 / 16

         B = 31 ± 33 / 16

         B = 64/16, -2/16

         B = 4, -1/8

Answer:

        So the value of B is 4 and -1/8 to satisfy the given expression.