Math, asked by kabhkia09, 11 months ago

b-[b-(a+b)-b(b-a+b)+2a)=?

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Answers

Answered by Thelunaticgirl
3
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=>b-[b-(a+b)-b(b-a+b)+2a)=>



= >b-(b-(a+b)-(b-(2b-a))+2a)

= >b-(b-(a+b)-(b-2b+a))+2a)

= >b-(b-a-b-b+2b-a)+2a)

= >b-(b-2b+2b-2a)+2a)

= >b-(b-2a)+2a)

=> b-(b-2a+2a)

= >b-b

==> 0

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Answered by Anonymous
4

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b - [ b - ( a + b ) - { b - ( b - a + b ) } +2a ]

b - { b - a - b - ( b - b + a - b ) + 2a }

b - { - a - ( - b + a ) + 2a }

b - ( - a + b - a + 2a )

b - ( -2a + b + 2a )

b + 2a - b - 2ab = 0

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