b-[b-(a+b)-b(b-a+b)+2a)=?
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=>b-[b-(a+b)-b(b-a+b)+2a)=>
= >b-(b-(a+b)-(b-(2b-a))+2a)
= >b-(b-(a+b)-(b-2b+a))+2a)
= >b-(b-a-b-b+2b-a)+2a)
= >b-(b-2b+2b-2a)+2a)
= >b-(b-2a)+2a)
=> b-(b-2a+2a)
= >b-b
==> 0
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4
b - [ b - ( a + b ) - { b - ( b - a + b ) } +2a ]
b - { b - a - b - ( b - b + a - b ) + 2a }
b - { - a - ( - b + a ) + 2a }
b - ( - a + b - a + 2a )
b - ( -2a + b + 2a )
b + 2a - b - 2ab = 0
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