Question

b. base 24 cm and equal sides 20 cm each find the area of the triangle
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Answer 1

Answer:

Step-by-step explanation:

Let ABC is an isosceles triangle.

AB = AC = 16 cm, BC = 20 cm

Draw AD⊥BC, such that BD = DC = 10 cm

Now, In right △ADB, By Pythagoras Theorem

AD² = AB² - BD²

Or, AD² = 16² - 10²

Or, AD² = 256 - 100

Or, AD² = 156

Or, AD = 2√39 cm

Area of the triangle = 1/2 × BC × AD

Or, Area of the triangle = 1/2 × 20 × 2√39

Or, Area of the triangle = 20√39

Or, Area of the triangle = 20×6.2449979984

Or, Area of the triangle = 124.899959968

Or, Area of the triangle = 124.90 cm²

Therefore, the area of the triangle = 124.90 cm²

Answer 2

Answer:

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