b) Based on the following data, find the values of the expressions [4 x 1 = 41 A B C D E F 1 Name Maths Physics Chemistry Total Percentage 2 Sakshi 85 82 90 3 Ankita 90 85 94 4 tim Priya 85 87 91 5 Akhila 89 83 88 6 Maximum Marks 7 Minimum Marks 1) In cell E2 as = SUM(B2:D2) and copy the function in cell E3 to E5 ii) In cell 12 as = (E2*100)/300 and copy the formula in cell F3 to F5 iii) In cell E6 as = Max(E2:E5) iv) In cell F7 as = Max(F2:F5)
Answers
Answered by
2
Answer:
M = int(input())
P = int(input())
C = int(input())
MP = M + P
MC = M + C
PC = P + C
if M >= 35 and P >= 35 and C >= 35 and (MP >= 90 or MC >= 90 or PC >= 90):
print('True')
else:
print('False')
Answered by
1
Explanation:
Let M, P and C denote the students studying Mathematics, Physics and Chemistry
And U represents total students
So, n(U)=200,
n(M)=120,n(P)=90
n(C)=70,n(M∩P)=40,n(P∩C)=30
n(M∩C)=50,n(M∪P∪C)
′
=20
∴n(M∪P∪C)
′
=n(U)−n(M∪P∪C)
⇒20=200−n(M∪P∪C)
⇒n(M∪P∪C)=180
⇒n(M∪P∪C)=n(M)+n(P)+n(C)
−n(M∩P)−n(P∩C)−n(C∩M)+n(C∩M∩P)
∴180=120+90+70−40−30−50+n(C∩M∩P)
⇒180=280−120+n(C∩M∩P)
⇒n(P∩C∩M)=300−280=20
Hence, the number of students studying all three subjects is 20.
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