b BC = CA = 12 cm, angle BCA = 90°
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Given : BC = CA = 12 cm, angle BCA = 90°
To Find : AB
Area of triangle
Solution:
Pythagoras' theorem: square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two perpendicular sides.
AB² = BC² + AC²
=> AB² = 12² + 12²
=> AB² = 12²(1 + 1)
=> AB² = 12²(2)
=> AB = 12√2
Length of AB = 12√2 cm
Area of triangle = (1/2) * BC * CA
= (1/2)*12 * 12
= 72 cm²
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