-b+c=1,a+3b+2c=0,a-2b-c=0 then find a,b,c values
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Answer:
a=(-2)
b= 0
c= 1
Explanation:
-b+c =1____(i)
a+3b+2c=0______(ii)
a-2b-c=0______(iii)
2c= a+3b
c= a+3b/2___(iv)
substitute value of c in eqn. (iii)
a- 2b-c =0.
a-2b-a+3b/2=0. (a-a=0)
-2b+3b /2=0
-b/2=0
-b=0×2
b=0____(v)
substitute value of b in eqn. (i)
-b+c=1
0+c=1
c=1
put value of b&c in eqn.(ii)
a+3b+2c=0
a+3(0)+2(1)=0
a+0+2=0
a=(-2).
hope it helps you...
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