Physics, asked by sreedharnethi70, 8 months ago

-b+c=1,a+3b+2c=0,a-2b-c=0 then find a,b,c values​

Answers

Answered by vrundapatel25
0

Answer:

a=(-2)

b= 0

c= 1

Explanation:

-b+c =1____(i)

a+3b+2c=0______(ii)

a-2b-c=0______(iii)

2c= a+3b

c= a+3b/2___(iv)

substitute value of c in eqn. (iii)

a- 2b-c =0.

a-2b-a+3b/2=0. (a-a=0)

-2b+3b /2=0

-b/2=0

-b=0×2

b=0____(v)

substitute value of b in eqn. (i)

-b+c=1

0+c=1

c=1

put value of b&c in eqn.(ii)

a+3b+2c=0

a+3(0)+2(1)=0

a+0+2=0

a=(-2).

hope it helps you...

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