(b+c)²/bc +(c+a)²/ca+(a+b)²/ab is to find if a+b+c=0
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esika:
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a+b+c=0
1. b+c=-a
2. a+b=-c
3. c+a=-b
-a^3/bc + -b^3/ca + -c^3/ab
=-(a^3+b^3+c^3)/abc
=-3abc/abc
=-3
1. b+c=-a
2. a+b=-c
3. c+a=-b
-a^3/bc + -b^3/ca + -c^3/ab
=-(a^3+b^3+c^3)/abc
=-3abc/abc
=-3
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