Question

B.
C. 35 m
3. A battery whose e.m.f. is 40 V has an internal resistance of 5 . If this batter
connected to a 15 2 resistor 'R', what will be the voltage drop across 'R'?
A. 10 V
D. 50 V
B. 30 V
E. 70 V
r
40 V​

Answer 1

Answer:

Total Resistance = Internal resistance + external resistance

R=5+15

R=20 Ω

Total current flowing in the circuit

I= E/R

I= 40/20=2

I=2 Amps.

Drop Across 15Ω resistor

V= IR

V=2 x 15

V=30 Volts

PLZ MARK AS BRAINLIEST ANSWER AND THX FOR THE SUPERB QUESTION

Answer 2

Explanation:

B.

C. 35 m

3. A battery whose e.m.f. is 40 V has an internal resistance of 5 . If this batter

connected to a 15 2 resistor 'R', what will be the voltage drop across 'R'?

A. 10 V

D. 50 V

B. 30 V

E. 70 V

r

40 V