Question

b+c-a/a,c+a-b/b,a+b-c/c​

Answer 1

Answer:

$(1) G.P. (2) A.P. (3) H.P. (4) A.G.P. Solution: Given (b+c-a)/a, (c+a-b)/b, (a+b-c)/c are in AP. Add 2 to all terms => (b+c-a)/a + 2, (c+a-b)/b + 2, (a+b-c)/c ... </p><p></p><p>$

Answer 2

Answer:

I don't know but you nide others help